(9-4x)/((2/x^2-3/x^3)*x^3)=-1

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Solution for (9-4x)/((2/x^2-3/x^3)*x^3)=-1 equation: 


D( x )

x^3 = 0

x^3*(2/(x^2)-(3/(x^3))) = 0

x^2 = 0

x^3 = 0

x^3 = 0

1*x^3 = 0 // : 1

x^3 = 0

x = 0

x^3*(2/(x^2)-(3/(x^3))) = 0

x^3*(2/(x^2)-(3/(x^3))) = 0

x^3*(2/(x^2)-3*x^-3) = 0

x^3*(2*x^-2-3*x^-3) = 0

2*x^-2-3*x^-3 = 0

x^-2*(2-3*x^-1) = 0

-3*x^-1 = -2 // : -3

x^-1 = 2/3

-1 < 0

1/(x^1) = 2/3 // * x^1

1 = 2/3*x^1 // : 2/3

3/2 = x^1

x = 3/2

x^-2*(x-3/2) = 0

x^-2*x^3*(x-3/2) = 0

( x-3/2 )

x-3/2 = 0 // + 3/2

x = 3/2

( x^-2 )

1*x^-2 = 0 // : 1

x^-2 = 0

x należy do O

( x^3 )

1*x^3 = 0 // : 1

x^3 = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:3/2) U (3/2:+oo)

(9-(4*x))/(x^3*(2/(x^2)-(3/(x^3)))) = -1 // + 1

(9-(4*x))/(x^3*(2/(x^2)-(3/(x^3))))+1 = 0

(9-4*x)/(x^3*(2/(x^2)-3*x^-3))+1 = 0

(9-4*x)/(x^3*(2*x^-2-3*x^-3))+1 = 0

x^3*(2*x^-2-3*x^-3) = 0

2*x^-2-3*x^-3 = 0

x^-2*(2-3*x^-1) = 0

-3*x^-1 = -2 // : -3

x^-1 = 2/3

-1 < 0

1/(x^1) = 2/3 // * x^1

1 = 2/3*x^1 // : 2/3

3/2 = x^1

x = 3/2

x^-2*(x-3/2) = 0

(9-4*x)/(x^-2*x^3*(x-3/2))+1 = 0

(9-4*x)/(x^-2*x^3*(x-3/2))+(1*x^-2*x^3*(x-3/2))/(x^-2*x^3*(x-3/2)) = 0

1*x^-2*x^3*(x-3/2)-4*x+9 = 0

x^2-11/2*x+9 = 0

x^2-11/2*x+9 = 0

x^2-11/2*x+9 = 0

DELTA = (-11/2)^2-(1*4*9)

DELTA = -23/4

DELTA < 0

1 = 0

1/(x^-2*x^3*(x-3/2)) = 0

1/(x^-2*x^3*(x-3/2)) = 0 // * x^-2*x^3*(x-3/2)

1 = 0

x belongs to the empty set

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